Optimal. Leaf size=116 \[ \frac {35 b^2 \tan ^{-1}\left (\frac {\sqrt {b x-a}}{\sqrt {a}}\right )}{4 a^{9/2}}+\frac {35 b^2}{4 a^4 \sqrt {b x-a}}-\frac {35 b^2}{12 a^3 (b x-a)^{3/2}}+\frac {7 b}{4 a^2 x (b x-a)^{3/2}}+\frac {1}{2 a x^2 (b x-a)^{3/2}} \]
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Rubi [A] time = 0.03, antiderivative size = 116, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {51, 63, 205} \begin {gather*} \frac {35 b^2 \tan ^{-1}\left (\frac {\sqrt {b x-a}}{\sqrt {a}}\right )}{4 a^{9/2}}+\frac {35 \sqrt {b x-a}}{6 a^3 x^2}+\frac {14}{3 a^2 x^2 \sqrt {b x-a}}+\frac {35 b \sqrt {b x-a}}{4 a^4 x}-\frac {2}{3 a x^2 (b x-a)^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 51
Rule 63
Rule 205
Rubi steps
\begin {align*} \int \frac {1}{x^3 (-a+b x)^{5/2}} \, dx &=-\frac {2}{3 a x^2 (-a+b x)^{3/2}}-\frac {7 \int \frac {1}{x^3 (-a+b x)^{3/2}} \, dx}{3 a}\\ &=-\frac {2}{3 a x^2 (-a+b x)^{3/2}}+\frac {14}{3 a^2 x^2 \sqrt {-a+b x}}+\frac {35 \int \frac {1}{x^3 \sqrt {-a+b x}} \, dx}{3 a^2}\\ &=-\frac {2}{3 a x^2 (-a+b x)^{3/2}}+\frac {14}{3 a^2 x^2 \sqrt {-a+b x}}+\frac {35 \sqrt {-a+b x}}{6 a^3 x^2}+\frac {(35 b) \int \frac {1}{x^2 \sqrt {-a+b x}} \, dx}{4 a^3}\\ &=-\frac {2}{3 a x^2 (-a+b x)^{3/2}}+\frac {14}{3 a^2 x^2 \sqrt {-a+b x}}+\frac {35 \sqrt {-a+b x}}{6 a^3 x^2}+\frac {35 b \sqrt {-a+b x}}{4 a^4 x}+\frac {\left (35 b^2\right ) \int \frac {1}{x \sqrt {-a+b x}} \, dx}{8 a^4}\\ &=-\frac {2}{3 a x^2 (-a+b x)^{3/2}}+\frac {14}{3 a^2 x^2 \sqrt {-a+b x}}+\frac {35 \sqrt {-a+b x}}{6 a^3 x^2}+\frac {35 b \sqrt {-a+b x}}{4 a^4 x}+\frac {(35 b) \operatorname {Subst}\left (\int \frac {1}{\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {-a+b x}\right )}{4 a^4}\\ &=-\frac {2}{3 a x^2 (-a+b x)^{3/2}}+\frac {14}{3 a^2 x^2 \sqrt {-a+b x}}+\frac {35 \sqrt {-a+b x}}{6 a^3 x^2}+\frac {35 b \sqrt {-a+b x}}{4 a^4 x}+\frac {35 b^2 \tan ^{-1}\left (\frac {\sqrt {-a+b x}}{\sqrt {a}}\right )}{4 a^{9/2}}\\ \end {align*}
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Mathematica [C] time = 0.01, size = 38, normalized size = 0.33 \begin {gather*} -\frac {2 b^2 \, _2F_1\left (-\frac {3}{2},3;-\frac {1}{2};1-\frac {b x}{a}\right )}{3 a^3 (b x-a)^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.12, size = 93, normalized size = 0.80 \begin {gather*} \frac {35 b^2 \tan ^{-1}\left (\frac {\sqrt {b x-a}}{\sqrt {a}}\right )}{4 a^{9/2}}-\frac {8 a^3-56 a^2 (b x-a)-175 a (b x-a)^2-105 (b x-a)^3}{12 a^4 x^2 (b x-a)^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.96, size = 260, normalized size = 2.24 \begin {gather*} \left [-\frac {105 \, {\left (b^{4} x^{4} - 2 \, a b^{3} x^{3} + a^{2} b^{2} x^{2}\right )} \sqrt {-a} \log \left (\frac {b x - 2 \, \sqrt {b x - a} \sqrt {-a} - 2 \, a}{x}\right ) - 2 \, {\left (105 \, a b^{3} x^{3} - 140 \, a^{2} b^{2} x^{2} + 21 \, a^{3} b x + 6 \, a^{4}\right )} \sqrt {b x - a}}{24 \, {\left (a^{5} b^{2} x^{4} - 2 \, a^{6} b x^{3} + a^{7} x^{2}\right )}}, \frac {105 \, {\left (b^{4} x^{4} - 2 \, a b^{3} x^{3} + a^{2} b^{2} x^{2}\right )} \sqrt {a} \arctan \left (\frac {\sqrt {b x - a}}{\sqrt {a}}\right ) + {\left (105 \, a b^{3} x^{3} - 140 \, a^{2} b^{2} x^{2} + 21 \, a^{3} b x + 6 \, a^{4}\right )} \sqrt {b x - a}}{12 \, {\left (a^{5} b^{2} x^{4} - 2 \, a^{6} b x^{3} + a^{7} x^{2}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.90, size = 97, normalized size = 0.84 \begin {gather*} \frac {35 \, b^{2} \arctan \left (\frac {\sqrt {b x - a}}{\sqrt {a}}\right )}{4 \, a^{\frac {9}{2}}} + \frac {2 \, {\left (9 \, {\left (b x - a\right )} b^{2} - a b^{2}\right )}}{3 \, {\left (b x - a\right )}^{\frac {3}{2}} a^{4}} + \frac {11 \, {\left (b x - a\right )}^{\frac {3}{2}} b^{2} + 13 \, \sqrt {b x - a} a b^{2}}{4 \, a^{4} b^{2} x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.02, size = 92, normalized size = 0.79 \begin {gather*} -\frac {2 b^{2}}{3 \left (b x -a \right )^{\frac {3}{2}} a^{3}}+\frac {35 b^{2} \arctan \left (\frac {\sqrt {b x -a}}{\sqrt {a}}\right )}{4 a^{\frac {9}{2}}}+\frac {6 b^{2}}{\sqrt {b x -a}\, a^{4}}+\frac {13 \sqrt {b x -a}}{4 a^{3} x^{2}}+\frac {11 \left (b x -a \right )^{\frac {3}{2}}}{4 a^{4} x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 2.87, size = 121, normalized size = 1.04 \begin {gather*} \frac {105 \, {\left (b x - a\right )}^{3} b^{2} + 175 \, {\left (b x - a\right )}^{2} a b^{2} + 56 \, {\left (b x - a\right )} a^{2} b^{2} - 8 \, a^{3} b^{2}}{12 \, {\left ({\left (b x - a\right )}^{\frac {7}{2}} a^{4} + 2 \, {\left (b x - a\right )}^{\frac {5}{2}} a^{5} + {\left (b x - a\right )}^{\frac {3}{2}} a^{6}\right )}} + \frac {35 \, b^{2} \arctan \left (\frac {\sqrt {b x - a}}{\sqrt {a}}\right )}{4 \, a^{\frac {9}{2}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.07, size = 117, normalized size = 1.01 \begin {gather*} \frac {35\,b^2\,\mathrm {atan}\left (\frac {\sqrt {b\,x-a}}{\sqrt {a}}\right )}{4\,a^{9/2}}-\frac {\frac {2\,b^2}{3\,a}-\frac {175\,b^2\,{\left (a-b\,x\right )}^2}{12\,a^3}+\frac {35\,b^2\,{\left (a-b\,x\right )}^3}{4\,a^4}+\frac {14\,b^2\,\left (a-b\,x\right )}{3\,a^2}}{2\,a\,{\left (b\,x-a\right )}^{5/2}+{\left (b\,x-a\right )}^{7/2}+a^2\,{\left (b\,x-a\right )}^{3/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 11.22, size = 1108, normalized size = 9.55
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
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